My friend has asked me a very interesting program. I would like to share that with you... (Not the very difficult problem though).
Problem: With a combination of five numbers 1, 2, 3, 4, 5 all the possible sequences in ascending order should be displayed. i.e.; (1, 1, 1, 1, 1), (1, 1, 1, 1, 2), and.... (5, 5, 5, 5, 5).
First we need to find out all the possible sequences availabe and then find out wheather they're in the ascending order.
Problem: With a combination of five numbers 1, 2, 3, 4, 5 all the possible sequences in ascending order should be displayed. i.e.; (1, 1, 1, 1, 1), (1, 1, 1, 1, 2), and.... (5, 5, 5, 5, 5).
First we need to find out all the possible sequences availabe and then find out wheather they're in the ascending order.
public class ArrayListSort
{
public static void main(String args[])
{
int a[]={1,2,3,4,5};
int count = 0;
for(int x:a)
{
for(int y:a)
{
for(int z:a)
{
for(int p:a)
{
for(int q:a)
{
int arr[]={x, y, z, p, q};
if(isArrayInSortOrder(arr))
{
System.out.println("("+x+", "+y+", "+z+", "+p+", "+q+")");
count++;
}
}
}
}
}
}
System.out.println("Total number of combinatios: "+count);
}
public static boolean isArrayInSortOrder(int a[])
{
boolean valid = true;
for(int i=0;i<a.length;i++)
{
for(int j=i;j<a.length;j++)
{
if(a[i]>a[j])
{
valid = false;
break;
}
}
}
return valid;
}
}
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